3 ms·
But an implementation where sizeof(int) == sizeof(long) == sizeof(long long) is allowed by the specification.
by dezgeg 12y ago
But an implementation where sizeof(int) == sizeof(long) == sizeof(long long) is allowed by the specification.
- marvy 12y agoOn a (slightly) more practical level: there exists some largest integer type. You may someday need to sort it. If you want your sort to always work, you can't afford to overflow.