4 ms·
If you use a std::List<T>, doesn't it uses nodes like T data p next p previous p owner anyway? It shouldn't create a pointer to the data, just
by ant6n 12y ago
If you use a std::List<T>, doesn't it uses nodes like
T data
p next
p previous
p owner
anyway? It shouldn't create a pointer to the data, just like a std::vector<T> isn't an array of pointers to T.
- desdiv 12y agoLet's say I have a bunch of Bullet objects, and each Bullet belongs to multiple lists. In that case, std::list<Bullet> doesn't work and I have to use std::list<Bullet*> instead, thus the extra pointer dereference.
- SamReidHughes 12y agoOnly without the owner pointer. But intrusive lists don't need an owner pointer either.