3 ms·
You're right, I messed that one up. But as log(a + b) /= log(a) + log(b) in general, the result is still correct.
by filmor 12y ago
You're right, I messed that one up. But as
log(a + b) /= log(a) + log(b)
in general, the result is still correct.
- quarterwave 12y agoYes, agree that log() wouldn't result from a linear operator. The idea behind my question: does the Shannon entropic integral correspond to the L2 length of some projected state? Leading to a prescription to prepare a state with minimum uncertainty product of canonically conjugate physical quantities. Afaik, in classical statistical physics the log() shows up when the N! in a binomial probability distribution limits to large N via the Stirling approximation. It would be interesting to find a different route for log() to enter the picture from a quantum standpoint. All admittedly vague and hand waving speculation.