3 ms·
The state of an HLL is completely determined by the set of distinct symbols that appear, not the order or the frequency of those symbols. So, inserting a billi
by nickharvey 12y ago
The state of an HLL is completely determined by the set of distinct symbols that appear, not the order or the frequency
of those symbols. So, inserting a billion A's and a single B into an HLL will have exactly the same outcome as inserting a bllion B's and a single A, or even just a single A and a single B.
Does this address your concern, or did I misunderstand your point?