3 ms·
slightly shorter javascript: for (var i=0; i++<100;) console.log((!(i%3)&&'Fizz'||'')+(!(i%5)&&'Buzz'||'')||i);
by pablovidal85 12y ago
slightly shorter javascript:
for (var i=0; i++<100;) console.log((!(i%3)&&'Fizz'||'')+(!(i%5)&&'Buzz'||'')||i);