3 ms·
Wikipedia actually supports his usage on a more definitive page http://en.wikipedia.org/wiki/Almost_all http://en.wikipedia.org/wiki/Almost_all. Speaking as an
by moomin 12y ago
Wikipedia actually supports his usage on a more definitive page http://en.wikipedia.org/wiki/Almost_all http://en.wikipedia.org/wiki/Almost_all. Speaking as an ex-mathematician, I started laughing as soon as I read the title, because it pretty much tells you how to demonstrate it.