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No that's BS. `std::string` should be used where ever it is applicable. The whole issue that this post about chrome was talking about was dealing with a poor u
by zl4000 12y ago
No that's BS. `std::string` should be used where ever it is applicable.
The whole issue that this post about chrome was talking about was dealing with a poor usage of `std::string`, such as passing c_str() to then go and construct another string instead of passing by const ref.
Or building a set of `std::string` to simply check if a value exists.
That's just shit code, not an issue with `std::string`.
- vegancap 12y agoRight, I guess I misunderstood the article. As I said, new to C++.
- humanrebar 12y agoThere's a right way to do it. It's not the obvious way. Berating people for coming to terms with that isn't helpful. It's not their fault that C++ only really supports std::string out of the box. What are the alternatives? 1. const std::string & : what if I have a vector<char>? 2. const char * : what if it's not null terminated? 3. const char * and size_t : Better, but what if I have a deque<char>? 4. const char * start, const char * stop : Better because you can write algorithms around this, but still, doesn't help with deque<char>? 5. template on START_ITER and STOP_ITER : The best we have now if you need an extremely general solution. But I hope writing your implementation in headers is fine. 6. home grown type : a very popular choice, but http://xkcd.com/927/ http://xkcd.com/927/ 7. boost::string_ref : maybe the best choice, as it can be created from 1-4 (and most 6's), but still doesn't work with deque<char>. ...so give the rookie a break. But I'll support any comment in a code review about not accepting std::string by reference or by value in an interface.
- nightcracker 12y ago#5 and many, many other reasons is why C++ desperately needs a standardized range type. Let's pray it comes in C++17.
- pja 12y agoWhat would a range type offer over a pair of iterators?
- humanrebar 12y agocout << takeFirstN(sort(myVector), 10) << '\n'; ...try that with iterators.