Cool! Yeah, I considered pointing out that 84/53 is an especially good approximation for its complexity (since the next in the sequence uses much bigger integer

Cool! Yeah, I considered pointing out that 84/53 is an especially good approximation for its complexity (since the next in the sequence uses much bigger integers) -- but how are you going to deal with 53 notes, or even 41? It's neat to hear that others were not stopped by that. (It did occur to me you could almost label them with letters of the alphabet, with one left over: 53=26x2+1. But that'd be silly and invite confusion with the 12-tone note names.)