3 ms·
Nice demo! Quick back of the envelope calculation for the current to overcome dynamic friction: I = mu_friction * Mass * grav_acc / (Turns_per_length * Area *
by quarterwave 12y ago
Nice demo! Quick back of the envelope calculation for the current to overcome dynamic friction:
I = mu_friction * Mass * grav_acc / (Turns_per_length * Area * Br_magnet)
Say Mass=0.1kg, coil at 600 turns per metre, hand-wave mu_friction=0.2, and a rare-earth retention Br=1Tesla, gives a current of 3A. Maybe more to chug along, would deplete a 2000mAh battery in about 30 minutes. Wire looks about 20 AWG, should get quite hot.
- scoot 12y agoWhich would theoretically use more energy, levetating the "train", or overcoming the friction? (I"m not suggesting this design can levitate, just curious about the trade-off.)
- nightcracker 12y agoThe train never levitates.
- CraigJPerry 12y agoLevitating. Since overcoming the friction can be achieved through approaches like coating the wire in ultra low friction material which will consume no power to operate.