3 ms·
The resolution of both sinusoids in the example you suggest is exactly 16bits Edit: While it would be possible to represent each of those individual sinusoids
by hamiltonkibbe 12y ago
The resolution of both sinusoids in the example you suggest is exactly 16bits
Edit:
While it would be possible to represent each of those individual sinusoids in 6 and 10 bits individually, the signal you describe has the high frequency signal "riding on " the low frequency signal. you need 16 bits to represent the amplitude of that signal at e.g. t = pi/4.
- deleted 12y ago[deleted]
- TD-Linux 12y ago2^10 + 2^6 = 1088. You only need 11 bits to not clip with that signal.
- hamiltonkibbe 12y agoyou'd need 11 bits to encode the signal at 0dBFS. Theres amplitude information stored in those other 5 zeros...