3 ms·

Using air humidity? Say we have 10 grams of water per cubic meter of air (so about 1% of the total air mass), so about 1 gram of hydrogen. At about 140 kJ/kg,

Using air humidity? Say we have 10 grams of water per cubic meter of air (so about 1% of the total air mass), so about 1 gram of hydrogen. At about 140 kJ/kg, and assuming a 10% reduction efficiency, and 100 watts per square meter solar panel, it should be able to reduce 0,071 grams per second or 260 grams per hour. Assuming 10% of air moisture can be extracted, the wind passing through the system to keep the water flow would need to be about 0,7 m/s. It's almost always as windy as that. The rough numbers are frighteningly good. All we need is the system to be cheap.

danieltillett 12y ago
... and some way to store and transport hydrogen. We can make hydrogen quite cheaply right now (it is kindergarten technology), but once you try to store and/or transport it then this is where things get really, really difficult [1]. 1. http://en.wikipedia.org/wiki/Hydrogen_storage http://en.wikipedia.org/wiki/Hydrogen_storage
- Gravityloss 12y ago
  No, I assumed (in hindsight could have mentioned it) that you could use the hydrogen locally to generate electricity. The thing is connected to the the electricity network. But I realized that is roughly the momentary day power of the panel. The real yearly average production is maybe 15% of that. Forgot the panel efficiency with this http://en.wikipedia.org/wiki/Photovoltaic_system#mediaviewer/File:SolarGIS-Solar-map-World-map-en.png http://en.wikipedia.org/wiki/Photovoltaic_system#mediaviewer...