4 ms·
Very nice! Another easy one is looking at it modulo 4. The powers on the left-hand side are both odd perfect squares, which are thus 1 modulo 4. So their sum i
by ggchappell 12y ago
Very nice!
Another easy one is looking at it modulo 4. The powers on the left-hand side are both odd perfect squares, which are thus 1 modulo 4. So their sum is 2 modulo 4. But the right-hand side is an even perfect square, which is 0 modulo 4.
EDIT. I guess my modulo-100 discussion is really just a convoluted way of coming up with the above fact.
- Chinjut 12y agoSo it turns out not only could we ignore all but the last digits of the bases... we could furthermore ignore all but the last digits of the exponents!