3 ms·

> There is not a fixed state of each 'quarter' in each 'box'. They are truly not determined until one is resolved; Isn't that unknowable? And aren't both situa

• sls 12y ago
  No. What you are calling 'fixed' is a local hidden variable - an internal state that has yet to be measured but is already determined. This state of affairs is ruled out by Bell's Theorem - https://en.wikipedia.org/wiki/Bell%27s_theorem https://en.wikipedia.org/wiki/Bell%27s_theorem
  • yohanatan 12y ago
    That's only true if you take the Copenhagen interpretation. There are other interpretations (like 'consistent histories' for example). See: http://en.wikipedia.org/wiki/Copenhagen_interpretation#Alternatives http://en.wikipedia.org/wiki/Copenhagen_interpretation#Alter...
    • om2 12y ago
      Other interpretations of quantum mechanics do not generally violate Bell's Theorem, since it appears to be confirmed by experiment. There are other interpretations which choose to abandon locality rather than hidden variables, such as the De Broglie-Bohm pilot wave interpretation. But consistent histories doesn't even do that. It's actually pretty similar to the Copenhagen interpretation.
      • yohanatan 12y ago
        I didn't say anything about violating Bell's theorem. Yes pilot wave theory is a better alternative that doesn't require spooky action at a distance but consistent histories doesn't require wavefunction collapse (which is a huge source of spookiness as well).