> Would you help me understand why this isn't closer to the security of a random 6 character password? There are about 80 characters you can type, so a 6 chara

> Would you help me understand why this isn't closer to the security of a random 6 character password? There are about 80 characters you can type, so a 6 character secret has 262,144,000,000 permutations (80^6) which is about 38 bits (2^38 is 274,877,906,944). 2^60 is much larger: 1,152,921,504,606,846,976 and its sixth root is 1024. So 1,024 memorable "characters" are needed. There are about 4000 unique word-based three letter prefixes: $ cut -c 1-3 /usr/share/dict/words | tr 'A-Z' 'a-z' | uniq | wc -l 4051 So 1,024 of those being associated with memorable words seems credible.