6 ms·
Think of it a a $2500 5k monitor shipping with a computer for free
by burntcookie90 12y ago
Think of it a a $2500 5k monitor shipping with a computer for free
- izacus 12y agoUnfortunately you can't hook up a powerful workstation to that monitor :/
- jpb0104 12y agoIf this holds true you should be able to: http://support.apple.com/kb/ht3924#12 http://support.apple.com/kb/ht3924#12
- jsheard 12y agoI don't think that will work here - TB2 is derived from DP1.2, which only goes up to 4K@60hz. You'll have to wait for TB3 to drive an external 5K monitor from a Mac.
- gambiting 12y agoLike I have posted elsewhere already: 5120x2880 = 14745600 pixels 14745600pixels x 3 colours, 1 byte each = 44236800 bytes 44236800/1024/1024 = 42.19MB each frame 42.19MB per frame x 60 frames a second = 2531.25MB. TB2 has a bandwidth of 20Gbps = 2560MB/s So yeah, theoretically TB2 has enough bandwidth. But it's a very tight fit.
- jsheard 12y agoDoesn't TB2 have two interleaved streams, one carrying DP1.2 and the other carrying 20Gbps PCI-E? Even if the PCI-E stream has enough bandwidth for 5K in theory, the ecosystem isn't in place to use it as a display output. That's what the DP part is for.
- milen 12y agoYou're ignoring signalling and overhead. The actual usable bandwidth is about 17.3Gbps, thus not enough (for 60fps uncompressed stream). DisplayPort v1.3 can deliver 25.92Gbps of usable bandwidth, thus required for 5k [1]. [1] http://www.extremetech.com/electronics/190130-displayport-1-3-unveiled-32-4-gbps-bandwidth-support-for-4k-60-fps-5k-and-8k http://www.extremetech.com/electronics/190130-displayport-1-...
- hamstergene 12y agoYou should divide 20Gbps by 9 bits (2275 MB/s) or even by 10 (2048 MB/s), not by 8, because in addition to useful payload, there are also packet headers and control packets being transferred. So it actually doesn't.
- mrb 12y ago"Packet headers and control packets" are not the reason you should divide by 10. The reason is that Thunderbolt uses 8b-10b encoding so 1 byte of data is transferred as 10 physical bits. Therefore the maximum theoretical usable bandwidth is 20e9/10/1024/1024 = 1907 MiB/sec. Then on top of that you have to deduct the overhead from packet headers and control packets so the real-world usable bandwidth is even less than 1970 MiB/sec...
- aortega 12y agoI believe 2560 is the post-coding bandwidth. Links are usually 3.125 Gbps before coding.
- richbradshaw 12y agoFor other people to play with this, just google "(5120 * 2880 * 3 * 60) bytes/s in Gib/s" to get the answer (just short of TB2s 20GiB/s assuming no overheads.
- deleted 12y ago[deleted]
- potatolicious 12y agoTDM is likely to break with this new machine. Thunderbolt 2 only has a theoretical max throughput of 20Gbps... Driving a 5K display @ 60Hz would require 98.88% of that throughput, which is unlikely to be sustained in IRL usage. I'd be all over this if Apple can confirm that the monitor is usable by external machines.
- lechevalierd3on 12y agoAt some point you could use the iMac as a screen can it still me done ?
- webXL 12y agoI would imagine as long as the video card has similar specs as the new iMac, and the computer had Thunderbolt 2, then yes (at 5k). Otherwise, it would be scaled somehow or just not work at all.
- highercenter 12y agoComputer for free? With Mac everything costs money, there is hardly no way to enjoy this piece of hardware without spending money to the Mac way of money sucking.. I enjoy my arch linux system every single day, and it never cost me a cent, there is no backdoors, money sucking thing going on at all. But, for those who believe the marketing slogan that everything with Mac is better, well, grab your wallet and join the idiots.