4 ms·

If the call-able values are looked up dynamically, both branches will always run up to call().

• jules 17y ago
  I don't understand what you mean. Can you elaborate?
  • silentbicycle 17y ago
    Well, I'm guessing that in your Python-ish pseudocode any code wrapped in curly braces is a lambda. I missed that when I commented. What I meant was that if you had code that ran to look up / generate those blocks, rather than just a literal block, it would always process both (even though only one is needed).
    • wlievens 17y ago
      You need lazy evaluation. If we assume that his {} blocks create lambda's, he's got it.
      • jules 17y ago
        Right, that was the idea.