3 ms·
Yes -- well, 1/2 the area of a unit circle, which is why I multiply by 2. I used Sage (http://www.sagemath.org/ http://www.sagemath.org/) to create these quick
by lutusp 12y ago
Yes -- well, 1/2 the area of a unit circle, which is why I multiply by 2. I used Sage (http://www.sagemath.org/ http://www.sagemath.org/) to create these quick results:
f(x) = sqrt(1-x^2)
2 * integrate(f(x),x,-1,1)
Sage replies: pi (Sage is smart enough to knows this result is equal to pi, so it doesn't provide a numerical approximation, but simply prints "pi").
plot(f(x),x,-1,1,gridlines=True,aspect_ratio=1)
Sage replies: http://i.imgur.com/GZdnT8z.png http://i.imgur.com/GZdnT8z.png
The function by itself produces a line equal to 1/2 the distance across a unit circle at the coordinate provided by x. Therefore a definite integral of the function on the interval -1 to 1 should produce an area equal to 1/2 that of a unit circle, or pi/2.
My Calculus tutorial: http://www.arachnoid.com/calculus/ http://www.arachnoid.com/calculus/
- kleim 12y agoOr you can do it quick and dirty with a simple Google search: https://www.google.com/search?q=y+%3D+sqrt%281-x^2%29 https://www.google.com/search?q=y+%3D+sqrt%281-x^2%29
- lutusp 12y agoA nice, convenient way to get the graph. For the integral: http://www.wolframalpha.com/input/?i=2+integrate%28sqrt%281-x%5E2%29%2Cx%2C-1%2C1%29 http://www.wolframalpha.com/input/?i=2+integrate%28sqrt%281-...