3 ms·
"Benford" not "Benson". :-) If I were to approach this from the point of view of actual proof, I'd note that the problem is one of representation. In base 2, t
by tjradcliffe 12y ago
"Benford" not "Benson". :-)
If I were to approach this from the point of view of actual proof, I'd note that the problem is one of representation. In base 2, the result is trivially true since the reverse of all powers of 2 is 1. In base 5, likewise, the reverse of all powers of 5 is 1. Base 10 = 2*5, which may or may not be significant...
- deleted 12y ago[deleted]
- Chinjut 12y agoThe (grandparent post's) claim was only for powers of 2; i.e., 1, 10, 100, 1000, etc., in binary.