Just to make sure I've got the terminology down. Objects correspond to locations in memory. 5 + 6 has operands which are rvalues (and thus not objects because

Just to make sure I've got the terminology down. Objects correspond to locations in memory. 5 + 6 has operands which are rvalues (and thus not objects because you can't take their address). if x is an int, then in the context of the expr 5+x, it is undergoing lvalue-to-rvalue conversion Did I get that right?