3 ms·
The last digit on the clock can only be 0 through 9. If you truncate your chart accordingly, 0 and 1 are represented more than 2 and 3. Or do you mean “the en
by valleyer 12y ago
The last digit on the clock can only be 0 through 9. If you truncate your chart accordingly, 0 and 1 are represented more than 2 and 3. Or do you mean “the entire seconds value” (for which this idea would work with four children) instead of “the last digit”?
- lutusp 12y agoTo avoid confusion, I used the expression "last digits".
- baddox 12y agoIt actually doesn't matter how many options are in your random number generator. You only get a normal distribution if the number of children you have divides the number of options in your generator. Even if you're using the seconds of a clock, it doesn't work for 7 children.
- lutusp 12y ago> It actually doesn't matter how many options are in your random number generator. It certainly does -- the larger the random number, the fairer the outcome is. > Even if you're using the seconds of a clock, it doesn't work for 7 children. For a digits range of 0 - 59? Plus the fallback in the face of a precocious child of adding the number of minutes * 60?