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I did give Hilbert curves a try at one point, what made me go with z-order instead is that there's an elegant way to convert between coordinates and z-order qua
by plesner 12y ago
I did give Hilbert curves a try at one point, what made me go with z-order instead is that there's an elegant way to convert between coordinates and z-order quads (which I'll describe in a later post) and I couldn't find something similar for Hilbert quads.