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by jibiki 17y ago
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Lame, I know.
- 10ren 17y agoIn your interview at a rope pyrochronography factory, they ask you how to time 45 minutes given two ropes that each take an hour to burn. (The ropes burn uneveningly and unequally. That is, half a rope won't necessarily burn in half an hour, and it won't necessarily be same amount of time as half of the other would take to burn - all you know is that the total time for one rope to burn is one hour.)
- whatusername 17y agoOkay - I'm stumped. Care to share the answer? (maybe in a day or so -- to allow others to attempt to puzzle it out?)
- thisrod 17y ago(Encoded with rot13.) Yvtug ebcr 1 ng bar raq, naq ebcr 2 ng obgu raqf. Nsgre guvegl zvahgrf, ebcr 1 jvyy ohea bhg. Gura, yvtug gur bgure raq bs ebcr 2. Ebcr 2 oheaf bhg svsgrra zvahgrf yngre.
- nopassrecover 17y agoWell I think you mean: (rot13) Yvtug ebcr 1 ng bar raq, naq ebcr 2 ng obgu raqf. Nsgre guvegl zvahgrf, ebcr 2 jvyy ohea bhg. Gura, yvtug gur bgure raq bs ebcr 1. Ebcr 1 oheaf bhg svsgrra zvahgrf yngre. But even then: (rot13) Guvf nffhzrf gung Ebcr 1 ohearq svsgl creprag va gur gvzr vg gbbx ebcr 2 gb ohea. Vs ebcr 1 bayl ohearq bar dhnegre, gura vg jvyy gnxr gjragl-gjb naq n unys zvahgrf, abg svsgrra, nsgre yvtugvat gur bgure fvqr.
- roundsquare 17y ago(Rot 13) Anu, vg qbrfa'g nffhzr gung. Vs ebcr 1 gnxrf 1 ubhe gb ohea, naq lbh ohea vg sbe unys na ubhe, gura vg unf unys na ubhe yrsg bs ohea gvzr. Vg qbrfa'g znggre vs gur svefg unys ubhe gbbx hc 10%, 50% be 90% bs gur ebcr yratgu, vg jvyy fgvyy svavfu oheavat va nabgure unys ubhe.
- nopassrecover 17y agoOh yeah :-)
- aoeu 17y agoVg qbrfa'g znggre ubj zhpu ohearq va 30 zvaf - ol qrsvavgvba gur erznvavat ebcr (ubjrire ybat) jvyy nyfb ohea va 30 zvaf (be 15 jvgu obgu raqf yvg).
- nopassrecover 17y agoOh yeah :-)
- deleted 17y ago[deleted]
- roundsquare 17y agoHaha, when I read the question, my first thought was "he takes a knife and cuts it lengthwise. No wait... he might not have a knife. Hmmm..." It took me a while to realize that cutting it lengthwise was the whole problem.