4 ms·
P(A|B) != P(B|A), so not really a distance...
by pixcavator 19y ago
P(A|B) != P(B|A), so not really a distance...
- lsb 19y agoIt's from Cilibrasi and Vitanyi. They have shimming factors, so you take the min of A|B and B|A, then you throw in some logs to not penalize low probabilities.