Its worth noting that this force is not due to air preasure per se, but the difference in prrssure between the inner and outer volumes; if you can distribute th

Its worth noting that this force is not due to air preasure per se, but the difference in prrssure between the inner and outer volumes; if you can distribute the 'crush force' over a series of concentric partially pressured shells for example, the force is significantly reduced. ...not sure how it would apply to balloons, but its used in a number of things to contain high pressure on the inner ring.