4 ms·
Could you get around this by using many small vacuum-filled spheres instead of one large sphere?
by pkinsky 12y ago
Could you get around this by using many small vacuum-filled spheres instead of one large sphere?
- valarauca1 12y agoThe scaling of sphere SA to Volume isn't exactly linear, its more logarithmic Source: http://upload.wikimedia.org/wikipedia/commons/thumb/5/5f/Comparison_of_surface_area_vs_volume_of_shapes.svg/512px-Comparison_of_surface_area_vs_volume_of_shapes.svg.png http://upload.wikimedia.org/wikipedia/commons/thumb/5/5f/Com...
- pantalaimon 12y agosure, but many small spheres are heavier than a large one.
- dredmorbius 12y agoMore specifically: weight/lift ratio is a cube to square relationship. Lift increases with the cube of the radius, weight (of the envelope) with the square. So a collection of smaller spheres would have a higher mass.