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For calculating the number of combinations, it looks like they are simply using 100 choose 7, or C(100, 7) which yields 16,007,560,800. http://what-are-the-cha
by kqr2 12y ago
For calculating the number of combinations, it looks like they are simply using 100 choose 7, or C(100, 7) which yields 16,007,560,800.
http://what-are-the-chances.blogspot.com/2008/02/7-letter-words-and-8-card-suits.html http://what-are-the-chances.blogspot.com/2008/02/7-letter-wo...
- psychometry 12y agoThat doesn't take into account repeated letters. You actually want the number of 7-combinations of the multiset { A * 5, B * 3, C * 4, ... } or whatever the letter frequencies are. That's for the first draw from the bag.