> Let me expound on Shannon's Law... If you double your transmitted data by doubling your power to double your SNR That's not how the Shannon-Hartley Theorem g

> Let me expound on Shannon's Law... If you double your transmitted data by doubling your power to double your SNR That's not how the Shannon-Hartley Theorem goes. http://en.wikipedia.org/wiki/Shannon%E2%80%93Hartley_theorem http://en.wikipedia.org/wiki/Shannon%E2%80%93Hartley_theorem C = B log(1 + S/N) So doubling S (the signal) doesn't double C (the channel capacity). The improvement will always be less than this. If the signal to noise ratio is already fairly good, then the improvement of doubling the signal can be very small.