2 ms·
Because then you'd actually be low-passing the frequencies present in the image, instead of some random bits.
by thisjepisje 12y ago
Because then you'd actually be low-passing the frequencies present in the image, instead of some random bits.
- mbrock 12y agoHuh? If you can apply an FFT and apply a filter in the frequency domain, what's preventing you from applying the convolution in the spatial domain?