3 ms·
Does latitude and longitude not suffer from the same problem?
by gamegoblin 12y ago
Does latitude and longitude not suffer from the same problem?
- rtkwe 12y agoNo because latitude and longitude are infinitely precise only limited by the accuracy of the measuring instrument. With the binary search idea you proposed the dividing lines are more tightly packed longitudinally near the poles.
- gamegoblin 12y agoBut near the poles, 1 degree longitude specifies a much smaller span than at the equator. So with say, 4 digits per latitude and longitude, you can specify a much smaller region at the poles than the equator.
- TheLoneWolfling 12y agoAnd that's the problem. To get 10m accuracy at the equator, you'd need to get much greater than 10m accuracy at the poles. You're effectively wasting information. The surface area of the Earth is 5.10x10^8 km^2. In an ideal world, you could uniquely represent every 10m*10m area of the Earth - there are 5.1x10^12 such areas. log2(5.1x10^12) is about 42.2. So you're wasting about 1.8 bits of information (~4%). Not too bad, now that I calculate it out.
- gamegoblin 12y agoYes, I get that. I was responding to user rtkwe who said that latitude/longitude didn't waste information.
- rtkwe 12y agoLat. long. doesn't have a length limitation of the binary search system, 10:10 so the information isn't wasted because where the grid is sparser near the equator we just extend the decimal places.
- recursive 12y agoThat "extension" is itself the waste being discussed. Some places require more digits than others.