2 ms·
Not at all. Here is the equivalent pseudo code: Function1Async() .flatMap(a -> a, Function2Async(a)) .map( (a, b) -> nonAsync(a, b)) .flatMap(c -> Anothe
by spullara 12y ago
Not at all. Here is the equivalent pseudo code:
Function1Async()
.flatMap(a -> a, Function2Async(a))
.map( (a, b) -> nonAsync(a, b))
.flatMap(c -> AnotherThingAsync(c))
.error(e -> catch)
.complete( finally );
The real code would be a little more complicated but not much.