4 ms·
It would be easier to do this from an array of strings but I found an ugly inefficient way to do it from the characters in an arbitrary string: func randChar
by josephlord 12y ago
It would be easier to do this from an array of strings but I found an ugly inefficient way to do it from the characters in an arbitrary string:
func randChar(alphabet:String?)->String {
let alpha = alphabet ? alphabet! : "abcdefghijklmnopqrstuvwxyz"
let rand:Int = Int(arc4random_uniform(UInt32(countElements(alpha))))
var gen = alpha.generate()
for i in 0..<rand {
gen.next()
}
return String(gen.next()!)
}
mikeash obviously has the answer if the codepoints are consecutive.
This was quite annoying to do, more so than I expected. If you convert to UTF16 view you can alter the index by advanceBy but then I couldn't find an easy way to convert back from the UInt16 to a Character/String but mikeash also covers that. However I'm not sure that conversion to UTF16 is any less work internally than iterating through the index.