3 ms·
then square that 1-(1-x)^2 to be pedantic :) (i.e. if 10% of the population is mean, 19% (=100%-(100%-10%)^2) of random pairings have at least one mean person
by colanderman 12y ago
then square that
1-(1-x)^2 to be pedantic :) (i.e. if 10% of the population is mean, 19% (=100%-(100%-10%)^2) of random pairings have at least one mean person, not 1% (=10% squared))
I don't know of a simple term to describe that relation though; is there one?
- jacobolus 12y ago"Double that then subtract the square" just doesn’t have the same ring, huh?
- bryondowd 12y agoSquaring alone would work if you looked at the odds of both people being nice. If 90% of the population is nice, squaring it would give you 81% of pairings being nice, which matches the above example. Just have to take the glass half full perspective.
- lcedp 12y agoIDK, but it reads quite eloquently: "probability of not((x1 is mean) and (x2 is mean))"