4 ms·
We've used the same number for those different rotations. That does not do anything directly about irrational power p. If p is a rational number represented by
by NaNaN 12y ago
We've used the same number for those different rotations. That does not do anything directly about irrational power p.
If p is a rational number represented by m/n, then
360 / (m/n) * m = 360n
So there are multiples of 360 that are divisible by m/n, and we can get a unique complex number from z^p.
Now p is irrational, what happens? According to what you said, there are so many different graphs that can not be merged into just one.