> because obscure terms force you to refer solely to (and eventually internalise) a precise and abstract definition. Unless some C++ people decide that “functo

> because obscure terms force you to refer solely to (and eventually internalise) a precise and abstract definition. Unless some C++ people decide that “functor” is a wonderful name for a stateful function-like thing which somewhat resembles closures/lambdas but has nothing whatsoever to do with the functors from functional programming.