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I can trivially compute (x', E_{k'}(x')) for k' and x' of my choosing. True, I oversimplified a bit. I was referring to situations where you don't know k' and
by cperciva 12y ago
I can trivially compute (x', E_{k'}(x')) for k' and x' of my choosing.
True, I oversimplified a bit. I was referring to situations where you don't know k' and x', e.g., x' = x and k' = k ^ \epsilon for some value \epsilon.
- pdf_reader 12y agoOk, so what is the revised statement? "Referring to situations" is pretty vague...