> The Prisoner's Dilemma demonstrates that a Nash equilibrium solution is not always Pareto optimal. The "confess-confess" solution is the Nash equilibrium. You

> The Prisoner's Dilemma demonstrates that a Nash equilibrium solution is not always Pareto optimal. The "confess-confess" solution is the Nash equilibrium. You will always be better off screwing the other person over, whether they are honest or dishonest. The "deny-deny" solution is Pareto optimal. If both parties can somehow trust each other, they will both be better off selecting this solution. This part is very confusing to me. I've always understood that deny was the screw-over move in the prisoner's dilemma. But this segment suggests that confessing is a local optimum. Have I misunderstood the prisoner's dilemma all these years?