3 ms·
I'm torn as to whether to call that a 'hack' or not, since it's just a bit of math. [ exp(log(x)) == x; log(ab) == log(a) + log(b) ]
by crux_ 17y ago
I'm torn as to whether to call that a 'hack' or not, since it's just a bit of math. [ exp(log(x)) == x; log(ab) == log(a) + log(b) ]