4 ms·
Which leads us to that ugly a.equals(b) instead of sane a == b. When not abused, operator overloading is a bless.
by drdaeman 12y ago
Which leads us to that ugly a.equals(b) instead of sane a == b. When not abused, operator overloading is a bless.
- rmrfrmrf 12y agoExcept that a == b and a.equals(b) are two different things.