2 ms·
Here's the Mathematica version: PrBbeatsA[\[Alpha]a_, \[Beta]a_, \[Alpha]b_, \[Beta]b_] := \!\( \UnderoverscriptBox[\(\[Sum]\), \(i = 0\), \(\[Alpha]b\)] \Frac
by spitfire 12y ago
Here's the Mathematica version:
PrBbeatsA[\[Alpha]a_, \[Beta]a_, \[Alpha]b_, \[Beta]b_] := \!\(
\UnderoverscriptBox[\(\[Sum]\), \(i = 0\), \(\[Alpha]b\)]
\FractionBox[\(Beta[\[Alpha]a +
i, \[Beta]b + \[Beta]a]\), \(\((\[Beta]b + i)\) Beta[
1 + i, \[Beta]b] Beta[\[Alpha]a, \[Beta]a]\)]\)