3 ms·
I don't really understand why this page reports the received power in kW? This will inevitable result all reported power levels be some 10^-p with p > 3. Also
by datenwolf 12y ago
I don't really understand why this page reports the received power in kW? This will inevitable result all reported power levels be some 10^-p with p > 3.
Also Watt is not a very useful unit here. You want something like dB(mW) which is much handier to work with. Good thing is, you just have to look at the exponent to get a rough dB(mW) figure: 10·log_10(m) - (p-6)·10, p being the exponent, m being the mantissa; for a quick estimate let m = 5, 10·log_10(5) =~= 7. So for the p = -23 this gives about -167dB(mW), which is accurate enough.