Yeah, I commented right before bed. I thought of a bunch of problems with the average while trying to get to sleep. I was thinking since the size of an outlier

Yeah, I commented right before bed. I thought of a bunch of problems with the average while trying to get to sleep. I was thinking since the size of an outlier is constrained by fitting in 4 bytes, there must be a way to show the median is in some band of numbers around the average. I didn't think of a particularly useful algorithm though. Thanks.