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Perhaps that was my fault. I don't think I was very clear. I was disagreeing with the statement that 'NaN' means the output of a function is not defined. Tha
by coherentpony 12y ago
Perhaps that was my fault. I don't think I was very clear. I was disagreeing with the statement that 'NaN' means the output of a function is not defined. That was the only thing I was disagreeing with. The rest of my comment tries to address some of the differences between the mathematical side and the computational side.
- manicdee 12y agoIs your point of disagreement down to the difference between "f(0) is undefined" versus "f can not be evaluated at 0"?
- coherentpony 12y agoYes. They are fundamentally different things.