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I think you just agreed with the comment you said "that's not true" to.
by vbuterin 12y ago
I think you just agreed with the comment you said "that's not true" to.
- lelandbatey 12y agoI disagree. I feel the parent did a great job of bridging explaining why the math is the way it is, and why our "intuition" is wrong.
- coherentpony 12y agoPerhaps that was my fault. I don't think I was very clear. I was disagreeing with the statement that 'NaN' means the output of a function is not defined. That was the only thing I was disagreeing with. The rest of my comment tries to address some of the differences between the mathematical side and the computational side.
- manicdee 12y agoIs your point of disagreement down to the difference between "f(0) is undefined" versus "f can not be evaluated at 0"?
- coherentpony 12y agoYes. They are fundamentally different things.