2 ms·
Isn't the key point here about isotropy, similar to the velocities in the ideal gas?
by quarterwave 12y ago
Isn't the key point here about isotropy, similar to the velocities in the ideal gas?
- mturmon 12y agoI think you're right, but it's really isotropy in combination with independence of x and y. Isotropy means you really are dealing with a function of r where r^2 = x^2 + y^2, and independence means the resulting function p(x,y) must factor as p(x) * p(y). This then forces the exponential form.