Just because the solutions are not guaranteed to have a closed form in radicals doesn't mean that my statement is false. In the field of real numbers any polyno

Just because the solutions are not guaranteed to have a closed form in radicals doesn't mean that my statement is false. In the field of real numbers any polynomial with a degree higher than two is reducible. http://en.wikipedia.org/wiki/Irreducible_polynomial#Real_and_complex_numbers http://en.wikipedia.org/wiki/Irreducible_polynomial#Real_and...