4 ms·
I think you mean eigenvalue of 0 for the stationary distribution.
by eoinmurray92 12y ago
I think you mean eigenvalue of 0 for the stationary distribution.
- tlarkworthy 12y agono http://en.wikipedia.org/wiki/Markov_chain#Stationary_distribution_relation_to_eigenvectors_and_simplexes http://en.wikipedia.org/wiki/Markov_chain#Stationary_distrib...
- eoinmurray92 12y agoYou are correct, I was thinking of the master equation of a Markov process. In that case the eigenvalue of 0 gives the stationary distribution under a spectral expansion
- tlarkworthy 12y agoGot any links on that? Sounds interesting. Does that calculate its dynamic properties or something?