4 ms·

What the heck is this? y: ~~~~~Foo

• akavel 12y ago
  I assumed it reads more or less like: Foo *****y; Or, probably, more like: std::unique_ptr<std::unique_ptr<std::unique_ptr<std::unique_ptr<std::unique_ptr<Foo>>>>> y;
  • kirab 12y ago
    Thanks, I hope this is never needed anywhere, ever.
    • pohl 12y ago
      I suspect it's a deliberately-perverse example, meant only to illustrate how deeply method calls will automatically dereference.
      • kzrdude 12y ago
        It also dereferences through ~~~&~@~~&~Foo.
  • claudius 12y ago
    Hey, at least you can write ‘>>>>>’ instead of ‘> > > > >’ now. :)
• alkonaut 12y ago
  y is a pointer to a pointer to a pointer to a pointer to a pointer to an instance of Foo. What the author wanted to show was that there is automatic dereference: z = y.foo() Will just reference through all five pointers and call the method on the object directly.
• masklinn 12y ago
  A pointer to a pointer to a pointer to a pointer to a pointer to a Foo.