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Without reading the paper or watching the video. > 1) What does it mean that entangled particles are supercorrelated? How can S(A|B) = 2 or -1? The density ma
by carlob 13y ago
Without reading the paper or watching the video.
> 1) What does it mean that entangled particles are supercorrelated? How can S(A|B) = 2 or -1?
The density matrix does not have the same properties of a joint probability distribution, so quantum entropy doesn't really have the same properties of classical entropy. [1]
> 2) The formula for Von Neumann entropy is S = -Tr(p log(p)), where p is the density matrix. How do you take a log of a matrix?
The log of a matrix is defined as the inverse of the matrix exponential. The matrix exponential can be defined as the usual power series, only using matrices rather than scalars.
What one usually does is: diagonalize the matrix (if possible), take the log of the eigenvalues and rotate again. Obviously taking the log of a matrix is a little trickier than the exponential because if you have negative or complex-valued eigenvalues you have to be a bit more careful.
[1] http://arxiv.org/abs/quant-ph/9610005 http://arxiv.org/abs/quant-ph/9610005
- tedsanders 13y agoThanks for the link - it's exactly what I needed!
- sinesha 13y agoGood answers. Just a small comment: quantum entropy is a generalization of classical entropy. In particular, if A and B are classically correlated, then S(A|B) has all the properties of a classical entropy (Shannon's, in this case), for instance, it is non-negative.
- tedsanders 13y agoWhat does classically correlated mean? Is it different than quantum correlated? (Is this analogous to the difference between pure and mixed states?)