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Although standard mathematica notation glosses over the difference, it's important to distinguish between the following two versions of the power operation, whi
by bumbledraven 13y ago
Although standard mathematica notation glosses over the difference, it's important to distinguish between the following two versions of the power operation, which I'll call pow1 and pow2:
pow1(x, y) = x^y where y is any integer
pow2(x, y) = x^y where y is any real
The value of 0^0 is 1 for (pow-a) and 0 for (pow-b).
- SamReidHughes 13y agoBut lim x->0 (x^x) = 1. Why should 0^0 be 0 then?