2 ms·
But what if you're in a context where you're not reasoning about continuous functions at all? Why would you have to be subject to reasoning that doesn't apply t
by j2kun 13y ago
But what if you're in a context where you're not reasoning about continuous functions at all? Why would you have to be subject to reasoning that doesn't apply to your situation?
- einhverfr 13y agoThat's actually an interesting point. And actually it occurs to me that even in continuous equations you have a problem: Does it matter if we are talking 0^x or x^0? I would think that in the context of 0^x, you'd have a constant function of 0, but x^0 you'd have a constant function of 1. These have different limits as x -> 0. I think you have just convinced me that 0^0 is undefined. Edit: Ouch. 0^x can't be defined for a negative x, so that doesn't work. I am back to siding with 1.